Forum to discuss all matters relating to the MPC1000 and MPC2500 operating systems created by 'JJ' (all versions).
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By Antonym Sat Jun 23, 2007 4:03 pm
make your ring modulation hum in tune with your song:

The note-naming convention specifies a letter, any accidentals (sharps/flats), and an octave number. Any note is an integer of half-steps away from middle A (A4). Let this distance be denoted n. If the note is above A4, then n is positive; if it is below A4, then n is negative. The frequency of the note (f), measured in Hz, is then:

f = 2n/12 × 440 Hz

For example, one can find the frequency of C5, the first C above A4. There are 3 half-steps between A4 and C5 (A4 → A♯4 → B4 → C5), and the note is above A4, so n = +3. The note's frequency is:

f = 23/12 × 440 Hz ≈ 523.2511 Hz.

you can be off by decimal points and still get a convincing result, i imagine.
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By primebeatz Sat Jun 23, 2007 4:44 pm
Antonym wrote:make your ring modulation hum in tune with your song:

The note-naming convention specifies a letter, any accidentals (sharps/flats), and an octave number. Any note is an integer of half-steps away from middle A (A4). Let this distance be denoted n. If the note is above A4, then n is positive; if it is below A4, then n is negative. The frequency of the note (f), measured in Hz, is then:

f = 2n/12 × 440 Hz

For example, one can find the frequency of C5, the first C above A4. There are 3 half-steps between A4 and C5 (A4 ? A?4 ? B4 ? C5), and the note is above A4, so n = +3. The note's frequency is:

f = 23/12 × 440 Hz ? 523.2511 Hz.

you can be off by decimal points and still get a convincing result, i imagine.
Can I get the English translation for that?
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By Antonym Sat Jun 23, 2007 5:10 pm
unfortunately some of the characters didn't copy well. i'll say more later
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By no7exit Sat Jun 23, 2007 5:22 pm
man, this is exciting. I cant wait to try this. Damn, why do i have to work today!